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Old 11-23-2009, 11:53 PM   #1
SDchargers
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Math gurus, please help

So I know there are some math wizards here. I'm stuck on a logarithm problem. Any one here good at math? You're help is appreciated. If you can include the steps getting you there instead of just the answer it would help me learn how to solve another one of these problems I have. Thanks in advance if anyone can answer this.

Express 2/3[ln(x^2-9) - ln(x+3)] + ln(x+4) as a single logarithm.

This is as far as I've got. I know at some point I have to use the quotient rule but at this point I'm just stuck if I'm even right at this point.

= 2/3ln(x^2-9) - 2/3ln(x+3) + ln(x+4)

= ln[(x^2-9)^(2/3)] - ln(x+3)^(2/3) + ln(x+4)
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Old 11-23-2009, 11:54 PM   #2
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Old 11-24-2009, 12:00 AM   #3
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I might be a bit rusty..

ln|(((x^2-9)/(x+3))^(2/3))*(x+4)|
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Old 11-24-2009, 12:06 AM   #4
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Here's the work:

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Old 11-24-2009, 12:07 AM   #5
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Sorry that should be x not equal to -3, not 3
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Old 11-24-2009, 12:08 AM   #6
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Old 11-24-2009, 12:10 AM   #7
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CMT is correct.

Damn, he wrote it up and scanned it and everything. Props. You should PayPal him a donation.
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Old 11-24-2009, 12:17 AM   #8
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Quote:
Originally Posted by CMT1729 View Post
I might be a bit rusty..

ln|(((x^2-9)/(x+3))^(2/3))*(x+4)|

Thank you CMT, with your help I see exactly where I went wrong. I really have to bow down to people who know this stuff like it's nothing.
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Old 11-24-2009, 12:19 AM   #9
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should have been more quick with it, I majored in math after all.
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Old 11-24-2009, 12:27 AM   #10
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Old 11-24-2009, 12:56 AM   #11
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Here's what I've learned about math so far.









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